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What is the spring constant (in n/m) of a spring that stores 100 J of elastic potential energy when it is stretched 5 m?

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Answer:

8N/m

Step-by-step explanation:

The elastic potential energy stored can be calculated using the equation:

elastic potential energy = 0.5 × spring constant × (extension)2

assuming it is not stretched beyond the limit of proportionality.

Then calculate using the values in the question:

100J = 0.5 × spring constant × 5²

200J = spring constant × 25

spring constant = 200J ÷ 25m²

spring constant = 8J/m²

spring constant = 8N/m

User Randy Minder
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