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How much energy is required to vaporize 0.5kg of water?
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How much energy is required to vaporize 0.5kg of water?

User Tnschmidt
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1 Answer

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Answer:

Step-by-step explanation:

Vaporization Equation => Q = m·ΔHv

m = 0.5Kg water = 500g water

ΔHv = Heat of vaporization = 540 calories/gram

∴Q = 500g x 540cal/g = 270,000 calories x 4.184 joules/cal = 1,129,680 joules = 1130 Kilojoules (3 sig. figs.)

User Metabble
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