Question

Find the equation of the line through A(4,12) and c(16,16)

Answer 1

Explanation:

m = y2 - y1/ x2 - x1

= 16 - 12 / 16 - 4

= 4/12 = 1/3

formula = y - y1 = m2 ( x - x1)

y - 12 = 1/3 ( x - 4)

y -12 = 1x/3 -4/3

y = 1x / 3 -4/3+12

= 1x/3 + 32/ 3

y = 1x/3 + 32/3