Answer:
a is formed above the eutecoid temperature as well (pro-eutecoid ferrite)
Thus ferrite is proeutectoid phase since 0.45 wt% C is less than 0.76 wt% C
b 7.487 kg of total ferrite
0.51273 kg of total cementite
c 4.62703 kg of total pearlite
3.35135 kg of total proeutectoid ferrite
Step-by-step explanation:
a) What is the proeutectoid phase
is formed above the eutecoid temperature as well (pro-eutecoid ferrite)
Thus ferrite is proeutectoid phase since 0.45 wt% C is less than 0.76 wt% C
(b) How many kilograms each of total ferrite and cementite form
Wα = CFe3C - Co = 6.70 - 0.45 = 0.93590
CFe3C - Cα 6.70 - 0.022
Which corresponds to 0.93590 x 8.0 kg = 7.487 kg of total ferrite
Similarly for total cementite
WCFe3C = Co - Cα = 0.45 - 0.022 = 0.006409
CFe3C - Cα 6.70 - 0.022
which corresponds to 0.006409 x 8. 0 kg = 0.51273 kg of total cementite
c) How many kilograms each of pearlite and the proeutectoid phase form?
considering the amount of pearlite and the proeutectoid phase ferrite formed
Wp = Co¹ - 0.022 = 0.45 - 0.022 = 0.5784
0.74 0.74
which corresponds to 0.5784 x 8. 0 kg = 4.62703 kg of total pearlite
Wα = 0.76 - 0.45 = 0.41892
0.74
which corresponds to 0.418.92 x 8. 0 kg = 3.35135 kg of total proeutetcoid ferrite