Question

Given the following equation: NaOH + HCl -> NaCl + H2O. Calculate the mass of water produced when 80.0 g of NaOH react with excess HCl.

Answer 1

36 grams

Step-by-step explanation:

Na 22.989

O 15.999

H 1.008 total 39.996 gm per mole

80 grams is 80 / 39.996 = ~ 2 moles

From the equation each mole of NaOH used results in ONE mole of H2O

so you will get two moles of H20

(1.008 *2 + 15.999) * 2 = ~ 36 gm