Question

Tan x * csc x = sec x

Answer 1

see explanation

Explanation:

using the identities

tanx =
`(sinx)/(cosx)` , cscx =
`(1)/(sinx)` , secx =
`(1)/(cosx)`

consider left side

tanx × cscx

=
`(sinx)/(cosx)` ×
`(1)/(sinx)` ( cancel sinx on numerator/ denominator )

=
`(1)/(cosx)` × 1

= secx = right side