Question

A bag contains 7 red marbles, 2 blue marbles and 5 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that both marbles drawn will be blue?A bag contains 7 red marbles, 2 blue marbles and 5 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that both marbles drawn will be blue?

Answer 1

The probability of drawing two blue marbles from the bag is 0.0714, or approximately 7.1%.

Step-by-step explanation:

To find the probability of drawing two blue marbles, we first need to find the total number of marbles in the bag.

The bag contains 7 red marbles, 2 blue marbles, and 5 green marbles, so the total number of marbles is 14.

Next, we need to find the number of ways to draw 2 blue marbles from the bag.

There are 2 blue marbles in the bag, so the number of ways to draw 2 blue marbles is C(2, 2) = 1.

Finally, we can calculate the probability by dividing the number of ways to draw 2 blue marbles by the total number of marbles in the bag:

Probability = (number of ways to draw 2 blue marbles) / (total number of marbles) = 1 / 14 = 0.0714.

Answer 2

1.2%

Step-by-step explanation:

List all the possible pairs and divide 1 by the sum.

Since there were 86 possible pairs,

1/86 is nearly equal to o.o12