Question

A spittlebug jumps into the air with an initial vertical velocity of 10 feet per second. The spittle bug reaches its maximum height after 0.3125 seconds. How high can it jump?

Answer 1

3.125 ft

Explanation:

Parameters given:

Initial velocity of spittlebug, v = 10 ft/s

Time taken to reach maximum height, t = 0.3125 s

To find the maximum height reached by the spittlebug we simply apply the formula for speed.

Speed is the time rate of displacement, in other words, how fast an object changes its position in a given time.

Speed = distance / time

Distance will then be:

Distance = speed * time

D = v * t

Hence, the maximum height reached by the spittlebug is:

D = 10 * 0.3125 = 3.125 ft