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A circle with center on the origin and point on (4,-2)

A circle with center on the origin and point on (4,-2)-example-1
User Alelom
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Answer:

Explanation:

Review the standard equation of a circle with center at (h, k) and radius r:

(x - h)^2 + (y - k)^2 = r^2

A point on (4, -2) has the radius r^2 = (4)^2 + (-2)^2, or r^2 = 20, or r = 2√5. Knowing the center is at (0, 0), we can write:

x^2 + y^2 = 20, or x^2 + y^2 = (2√5)^2

User Carlos Drew
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