Question

If you have 39.5g of Fe2O3 how many grams of co are requried to complete reaction

Answer 1

• 20.8g

Step-by-step explanation:

1. Balanced chemical equation

• Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

2. Convert 39.5g of Fe₂O₃ into moles

• #moles = mass in grams / molar mass

• molar mass of Fe₂O₃ = 159.69 g/mol

• #moles = 39.5g / 159.69g/mol = 0.24735 mol

3. Moles of CO

i) Mole ratio

• 3mol CO / 1 mol Fe₂O₃

ii) Set a proportion

• 3 mol CO / 1 mol Fe₂O₃ = x / 0.24735 mol Fe₂O₃

⇒ x = 0.24735mol Fe₂O₃ × 3mol CO / 1mol Fe₂O₃ = 0.7426 mol CO

4. Grams of CO

• molar mass CO: 28.01g/mol

• mass in grams = #moles × molar mass

• mass = 0.7426mol × 28.01g/mol = 20.8g ← answer