Question

The initial temperature of a 1.00 liter sample of argon is 293 K. The pressure is decreased from

720 mm Hg to 360 mm Hg and the volume increases to 2.14 liters. What was the final
temperature of the argon in Kelvin? ​

Answer 1

The final temperature of the Argon gas is 313.5 K.

Step-by-step explanation:

Using the ideal gas equation, we can find the final temperature of the Argon gas.

`$(P1V1)/(T1) = (P2V2)/(T2)`

Now we have to rearrange the equation to get T2 as,

`$ T2 = (P2V2T1)/(P1V1)\\`

P1 = Initial pressure = 720 mm Hg = 1 atm

P2 = Final Pressure = 360 mm Hg = 0.5 atm

V1 = initial volume = 1 L

V2 = Final Volume = 2.14 L

T1 = Initial Temperature = 293 K

T2 = Final Temperature = ?

Now we have to plugin the values as,

T2 =
`$(0.5 atm * 2.14 L * 293 K)/(1 atm *1 L)`

= 313.5 K

So the final temperature of the Argon gas is 313.5 K.