Question

A gas has a volume of 1.4 liters at STP. What is the new volume when the temperature is changed

to 40 K and the pressure is changed to 1.2 atm? ​

Answer 1

Answer : The new volume when the temperature is changed to 40 K and the pressure is changed to 1.2 atm is, 0.17 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1` = initial pressure of gas at STP = 1 atm

`P_2` = final pressure of gas = 1.2 atm

`V_1` = initial volume of gas at STP = 1.4 L

`V_2` = final volume of gas = ?

`T_1` = initial temperature of gas at STP = 273 K

`T_2` = final temperature of gas = 40 K

Now put all the given values in the above equation, we get:

`(1atm* 1.4L)/(273K)=(1.2atm* V_2)/(40K)`

`V_2=0.17L`

Therefore, the new volume when the temperature is changed to 40 K and the pressure is changed to 1.2 atm is, 0.17 L