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Quadratics practice, I need help on how to solve this

Quadratics practice, I need help on how to solve this-example-1
User Metro
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1 Answer

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Answer:

Below in bold.

Explanation:

x^2 - 2x - 3 = 0

(x - 3)(x + 1) = 0

The zeroes are -1, 3.

Change to vertex form:

= (x - 1)^2 - 1 - 3

= (x - 1)^2 - 4

So the axis of symmetry is x = 1.

The vertex is at (1, -4) and it is a minimum (because the coefficient of x^2 is positive).

Domain is (-∞, ∞)

Range is [-4, ∞).

Increasing when x < 1.

Decreasing when x > 1.

End behaviour x ---- -∞ , y --> ∞

x ----> ∞, y ---> ∞

User Yurii Verbytskyi
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