Question

A spinner has red, green, blue, and orange sections. The probability of landing on red is 2/3, on green is 1/12, on blue is 1/12. In simplest form, what is the probability of landing on orange?

Answer 1

Explanation:

P(landing on orange)=1 - [2/3 + 1/12 + 1/12]

`=1-[(2)/(3)+(2)/(12)]\\\\=1-[(2)/(3)+(1)/(6)]\\\\=1-[(2*2)/(3*2)+(1)/(6)]\\\\=1-[(4)/(6)+(1)/(6)]\\\\=1-[(4+1)/(6)]\\\\=1-(5)/(6)\\\\=(6)/(6)-(5)/(6)\\\\=(1)/(6)`