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A balloon is filled with 10 L of air at a pressure of 1400 torr. What is the pressure of the balloon if the volume is changed to 5 L?

User Albertina
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Final answer:

The pressure of a balloon filled with 10 L of air at 1400 torr will be 2800 torr when its volume is decreased to 5 L, as determined by Boyle's Law, which relates pressure inversely to volume.

Step-by-step explanation:

The question is based on the principles of Boyle's Law, which is a gas law, stating that the pressure and volume of a gas are inversely proportional to each other when the temperature and the amount of gas are held constant. For a balloon filled with 10 L of air at a pressure of 1400 torr, when the volume is changed to 5 L, we can predict the pressure change using Boyle's law.

Boyle's law is represented by the equation P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume. By rearranging the equation to solve for P2, we get P2 = P1V1 / V2.

Using the given values:

  • P1 = 1400 torr
  • V1 = 10 L
  • V2 = 5 L

We can calculate the new pressure:

P2 = (1400 torr × 10 L) / 5 L

P2 = 14000 torr·L / 5 L

P2 = 2800 torr

Therefore, the pressure of the balloon when the volume is changed to 5 L is 2800 torr.

User Usman Khalid
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