Question

Using the quadratic formula to solve 4x^2-3x + 9=2x + 1 what are the values of x​

Answer 1

x=5±√−103/8

Explanation:

There's no real solutions

4x2−3x+9−(2x+1)=2x+1−(2x+1)

4x2−5x+8=0

x=−b±√b2−4ac/2a

x=−(−5)±√(−5)2−4(4)(8)/2(4)

x=5±√−103/8