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How much energy is needed to heat 20.0 grams of water from 25.0°C to 50.0 °C?

2 Answers

2 votes
Yeah what he said is correct
User Chrysoula
by
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3 votes

Answer:

The answer to your question is Q = 2093 J

Step-by-step explanation:

Data

Energy = Q = ?

mass = 20 g

Temperature 1 = 25°C

Temperature 2 = 50°C

Specific heat = Cp = 4.186 J/g°C

Formula

Energy = Q = mCp(Temperature 2 - Temperature 1)

Substitution

Q = (20)(4.186)(50 - 25)

Simplification

Q = (20)(4.186)(25)

Result

Q = 2093 J

User Mstation
by
8.7k points

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