Answer:
672 g
Step-by-step explanation:
We can calculate the mass of water that can be warmed from 25.0°C to 37.0°C by the addition of 8,064 calories using the following expression.
![Q = c * m * \Delta T](https://img.qammunity.org/2021/formulas/chemistry/college/qv4wvs57p5wnp81j9hcowpjv4qsnj8rym7.png)
where,
c: specific heat of the water
m: mass
ΔT: change in the temperature
![m = (Q)/(c * \Delta T ) = (8,064cal)/((1cal/g. \° C) * (37.0 \° C - 25.0 \° C) ) = 672 g](https://img.qammunity.org/2021/formulas/chemistry/college/k2pi8yleh74txw66ruwoy5zqgyl8alcipw.png)
The mass of water that can be warmed under these conditions is 672 grams.