Question

2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2

How much AgCl could be obtained starting with 100g of each reactant.

Answer 1

It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

Step-by-step explanation:

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

`100 g \text { of } A g N O_(3) * \frac{2 \text { mol } A g N O_(3)}{169.87 g A g N O_(3)} * \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_(3)} * \frac{143.32 g A g C l}{1 \text { mol } A g C l}`

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.