Answer:
c. 6.2i - 4.2j
Explanation:
The vector projection when the angle θ not known can be calculated using the following property of the dot product:

Where the dot product of two vectors is given by:

And the magnitude of a vector is given by:

Using the previous definition, let's calculate the projection of w onto u:
First let's calculate the dot product between w and u:

Now let's find the magnitude of u:

So:

Therefore:
