1 Answer

Pibo · Answer 1 · 2021-10-23T19:46:56+0000

Answer:

$1.2646*10^(25)\ atoms$

Step-by-step explanation:

-The chemical formula for Molybdenum (V) Dichromate is
Mo(Cr_2O_7)_3

-There are 21 moles of oxygen per one mole of Molybdenum (V) Dichromate

-We apply Avogadro's constant to find the number of atoms of oxygen:

$Avogadro's \ Constant=6.022* 10^(23) \ mol_1\\\\No\ of \ Atoms=Moles* Avogadro's \ Constant\\\\=21* 6.022* 10^(23) \\\\=1.2646*10^(25)\ atoms$

Hence, there are
$1.2646*10^(25) \ atoms$

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