Question

Three liquids are at temperatures of 5 ◦C, 25◦C, and 34◦C, respectively. Equal masses of the first two liquids are mixed, and the equilibrium temperature is 17◦C. Equal masses of the second and third are then mixed, and the equilibrium temperature is 30.7 ◦C. Find the equilibrium temperature when equal masses of the first and third are mixed. Answer in units of ◦C.

Answer 1

m * c1 * (9 - 6) = m * c2 * (19 - 9) → mass m cancels

c2 = c1 * 3 / 10 = 0.3*c1

Step-by-step explanation:

However, for the second mix, there should be nothing from the first mix's answer except for 0.3c1. Essentially, the left side of the second mix equation should look like: m *0.3c1 * (31.1-19). Then, you can properly solve the equation.