73.5k views
5 votes
Lucy invested $30,000 in an account paying an interest rate of 6.6% compounded continuously. Assuming no deposits or withdrawals are made, how much money, to the nearest hundred dollars, would be in the account after 9 years?

2 Answers

2 votes

Final answer:

To calculate the final amount in the bank account, we can use the formula A = P(e(rt)), where A is the final amount, P is the principal amount, e is the base of natural logarithms, r is the interest rate, and t is the time in years. In this case, Lucy invested $30,000 at an interest rate of 6.6% compounded continuously for 9 years. By substituting these values into the formula and evaluating the expression, the final amount in the account after 9 years is approximately $53,509.79.

Step-by-step explanation:

To calculate the final amount in the bank account, we can use the formula: A = P(e(rt)), where A is the final amount, P is the principal amount, e is the base of natural logarithms, r is the interest rate, and t is the time in years. In this case, Lucy invested $30,000 at an interest rate of 6.6% compounded continuously for 9 years.

First, we need to convert the interest rate to a decimal by dividing it by 100: 6.6% = 0.066. Then, we can substitute the values into the formula: A = 30000(e0.066*9)). Using a calculator, we can evaluate this expression to get the final amount, which is approximately $53,509.79.

User Cromandini
by
6.1k points
0 votes

Answer:

A≈54300

Step-by-step explanation:

User Aemre
by
5.7k points