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6. A spring is originally 1.5 m long. It is stretched so that it is 1.8 m long. The spring constant is 50 N/m. Find the potential energy stored in the spring.
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40 votes
40 votes
6. A spring is originally 1.5 m long. It is stretched so that it is 1.8 m long. The spring constant is 50 N/m.

Find the potential energy stored in the spring.

User Elephantik
by
2.9k points

1 Answer

15 votes
15 votes

Answer:

PE = 1/2 K X^2

K = 50 N/m

X = .3 m

PE = 1/2 * 50 * .3^2 = 2.25 Joules

User Robert Newton
by
3.1k points
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