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What’s the minimum value of y=x^2 +4x + 4
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What’s the minimum value of y=x^2 +4x + 4

User Satish Modha
by
3.9k points

1 Answer

3 votes

Answer:

0

Explanation:

Convert to vertex form by completing the square.

y = x² + 4x + 4

y = (x + 2)² + 0

The vertex is at (-2, 0), so the minimum value is 0.

User AkinKaplanoglu
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