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6. A spring is originally 1.5 m long. It is stretched so that it is 1.8 m long. The spring constant is 50 N/m.

Find the potential energy stored in the spring.

User Clamum
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1 Answer

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Answer:

PE = 1/2 K X^2

K = 50 N/m

X = .3 m

PE = 1/2 * 50 * .3^2 = 2.25 Joules

User Raheem
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