Question

Second last question what is the area of this compound shape?​

Answer 1

43.12 yd²

Explanation:

Semicircle + triangle

½×pi×r² + ½×b×h

½(3.14)(4²) + ½(4)(9)

43.12 yd²

Answer 2

43.13 yd squared

Explanation:

This is a figure composed of a semicircle and a right triangle.

Triangle:

The area of a triangle is denoted by A = (1/2) * B * h, where b is the base and h is the height. Here, the base is actually also the radius of the semicircle, which is 4. The height is 9. Plug these in: A = (1/2) * 4 * 9 = 36/2 = 18 yd squared.

Semicircle:

The area of a semicircle is denoted by A =
`(1/2)\pi r^(2)`, where r is the radius. Here the radius is 4. So: A =
`(1/2)\pi *4^(2)=8\pi` ≈ 25.13 yd squared.

Adding these up: 18 + 25.13 = 43.13 yd squared

Hope this helps!