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What is the nth term rule of the quadratic sequence below?

-4, -3, 0, 5, 12, 21, 32

1 Answer

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Answer:

The nth term = n^2 - 2n - 3.

Explanation:

-4 -3 0 5 12 21 32

Differences 1 3 5 7 9 11

Difference 2 2 2 2 2 <-- divide this by 2 so its n^2.

So the first term is n^2

List the original numbers and values of n^2:

sequence -4 -3 0 5 12 21 32

n^2 1 4 9 16 25 36 49

Subtract -5 -7 -9 -11 -13 -15 -17

These last numbers have a common difference of -2 so the next part of the answer is -2n and get the -5, -7 etc we add -3.

So our formula is n^2 - 2n - 3.

Check for the 3rd term:

3rd term is 3^2 - 2(3) - 3 = 0.

5th term = 5^2 - 2(5) - 3 = 25 - 10 - 3 = 12.

User George Petrov
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