Question

Solve for an angle in right triangles help

Answer 1

64.62

Explanation:

AC²= AB²-BC²

`AC = \sqrt{ {(7)}^(2) - ({3)}^(2) }`

`= √(49 - 9) = √(40) = 2 √(10)`

`\tan(B) = (AC )/( BC)`

`B = { \tan}^( - 1) (2 √(10) )/(3)`

`= 64.62`

Answer 2

64.62 degrees

Explanation:

Cosine adjacent/hypotenuse (sides)

CosB = (3/7)

B =
`Cos^(-1)`(3/7)

B = 64.62