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What is the solution to the following system?

3x+10y-12z=40
x-5y=0
x-4z=0

1 Answer

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Answer:

(x, y, z) = (20, 4, 5)

Explanation:

The last two equations allow y and z to be expressed in terms of x, so we have ...

3x +2(5y) -3(4z) = 40

3x +2(x) -3(x) = 40

x = 20 . . . . . . . . . . . . divide by the coefficient of x

y = 20/5 = 4

z = 20/4 = 5

The solution is (x, y, z) = (20, 4, 5).

User Stephan Leroux
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