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Please someone help me with this, it’s due today

Please someone help me with this, it’s due today-example-1

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Answer:

~91 chirps/min

Explanation:

This exercise is asking us to estimate based on the values in the table. If we know the temperature is 65°F, let's find the closest values given to interpolate (assuming the data is fairly linear, which it appears to be).

Looks like the closest ones are 60° and 68°. We will look at their corresponding chirps/min and guess a number in between those two.

60° -> 81 chirps/min

68° -> 97 chirps/min

Because 65 is closer to 68 than 60, we expect our result to be closer to 97 than 81.

slope = rise/run


(97-81)/(68-60) =
(16)/(8) = 2 chirps/min/°F. So for every °F increase, we expect to increase by 2 chirps/min.

60+5 = 65, so let's add 2*5 = 10 chirps/min to 60 to get 91 chirps/min. This corresponds with what we would have guessed.

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