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5-3y=6 so (5-3y)^2 what is the missing number

5-3y=6 so (5-3y)^2 what is the missing number-example-1
User Matesio
by
8.3k points

2 Answers

2 votes

Answer:

36

Explanation:

1. First, let's solve 5 - 3y = 6

Step 1: Subtract 5 from both sides.


  • 5 - 3y - 5 = 6 - 5

  • -3y = 1

Step 2: Divide both sides by -3.


  • (-3y)/(-3) = (1)/(-3)

  • y = -(1)/(3)

2. Now, we plug in the value of y into (5 - 3y)^2


  • (5 - 3(-(1)/(3)))^2

  • (5+((-3)/(-3)))^2

  • (5+1)^2

  • (6)^2

  • 36

Therefore, the missing number is 36.

User Alliyah
by
8.3k points
11 votes

5 - 3y = 6

y = -1/3

(5 - 3 * -1/3)^2

6^2 = 36

answer is 36

User Claudio Pomo
by
8.6k points

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