g(x) be n
Now
Interchange x
Option D
(f + g)(x) is another way of writing f(x) + g(x).
Given that
(f + g)(x) = 10x + 7
f(x) = 6x + 2
it follows that
g(x) = (f + g)(x) - f(x)
g(x) = (10x + 7) - (6x + 2)
g(x) = 4x + 5
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