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How many moles of Ca(NO3)2 are there in 77.4 mL of 0.45 M solution? Round your answer to 3 decimal spaces, even if sig figs are not conserved. (Please answer quickly)
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How many moles of Ca(NO3)2 are there in 77.4 mL of 0.45 M solution?

Round your answer to 3 decimal spaces, even if sig figs are not conserved.
(Please answer quickly)

User Kpotehin
by
6.4k points

1 Answer

3 votes

Answer:

.03483 moles

Step-by-step explanation:

.45 * 77.4/1000 =

User Mickl
by
6.6k points
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