Answer:5000 s^-1
Explanation: Solution=
Using the formulae----> Kcat=Vmax/Et
where
Vmax is the maximum rate of the reaction when all the enzymes are saturated.
Vmax= 6.5 mmoles/s
Et=1.3 uM
1 mmole= 1000 umole
Changing to micromoles/sec, gives=
Vmax= 6.5 mmoles/s \times 1000= 6500 micromoles/s
Bringng back the equation,
----->Kcat= Vmax/Et
= 6500/1.3
= 5000 /s
Therefore, our answer is 5000 s^-1