Question

-2x^2+6x-3=0 with the quadratic formula


someone plz help

Answer 1

a = -2 b = 6 c = -3

x = -6 +- sq root (6^2 -4 * -2 *-3) / 2 * -2

x1 = [-6 + sq root (36 - 24)] / -4

x1 = [-6 + sq root (36 - 24)] / -4

x1 = (-6 + sq root (12) ) / -4

x1 = (-6 + 3.4641016151 ) / -4

x1 = -2.5358983849 / -4

x1 = 0.6339745962

x2 = (-6 - sq root (12) ) / -4

x2 = (-6 - sq root (12) ) / -4

x2= (-6 - 3.4641016151 ) / -4

x2 = - 9.4641016151 / -4

x2 = 2.3660254038

Explanation: