Answer:
![\Delta V = 7000\,L](https://img.qammunity.org/2021/formulas/spanish/high-school/a3ixz1g5jj9foo435bo5qmatsd2pn81s7d.png)
Step-by-step explanation:
El volumen de agua es directamente proporcional al nivel de agua. El volumen inicial de tanque se determina por regla de tres simple:
Volumen Nivel relativo
V 2/5
V-1600 1/3
![((2)/(5) )/((1)/(3) )\cdot (V-1600) = V](https://img.qammunity.org/2021/formulas/spanish/high-school/nhywn20c3i22h8dstvg1gn4g81h18hxko1.png)
![(6)/(5)\cdot (V-1600) = V](https://img.qammunity.org/2021/formulas/spanish/high-school/wcgqyr66bdqj1i50hwfey1ih88voitioho.png)
![6\cdot V - 9600 = 5\cdot V](https://img.qammunity.org/2021/formulas/spanish/high-school/as6w19vujsld1t97gwanp6sba4h0lujtsp.png)
![V = 9600\,L](https://img.qammunity.org/2021/formulas/spanish/high-school/gb5gvr9868dcke2xxbht5xfzzwr9dft3mu.png)
El nivel requerido para obtener un nivel relativo de 5/8 es:
![V = ((5)/(8) )/((2)/(5) )\cdot 9600 \,L](https://img.qammunity.org/2021/formulas/spanish/high-school/u9djxjeokvnovbycg2vsz5ombrindheumr.png)
![V = (25)/(16) \cdot (9600\,L)](https://img.qammunity.org/2021/formulas/spanish/high-school/5sd3jddqzvvwdi85jvcrv83nvfpiozozx8.png)
![V = 15000\,L](https://img.qammunity.org/2021/formulas/spanish/high-school/2ker1ice4kdxb8g6kqfa7co0ardccn7n7d.png)
La cantidad de agua a añadir es:
![\Delta V = 15000\,L - 8000\,L](https://img.qammunity.org/2021/formulas/spanish/high-school/e984wcv66594stgcrhdlharwhet897lai1.png)
![\Delta V = 7000\,L](https://img.qammunity.org/2021/formulas/spanish/high-school/a3ixz1g5jj9foo435bo5qmatsd2pn81s7d.png)