Question

What is the molality of 49 grams of NaCl in 469 grams of H2O (water)

Answer 1

Answer : The molality of sodium chloride is, 1.79 m

Explanation :

To calculate the molality of solution, we use the equation:

`\text{Molality}=\frac{m_(solute)* 1000}{M_(solute)* W_(solvent)\text{ (in grams)}}`

Where,

`m_(solute)` = Given mass of solute (sodium chloride) = 49 g

`M_(solute)` = Molar mass of solute (sodium chloride) = 58.5 g/mol

`W_(solvent)` = Mass of solvent (water) = 469 g

Now put all the given values in above equation, we get:

`\text{Molality of }NaCl=(49g* 1000)/(58.5g/mol* 469kg)\\\\\text{Molality of }NaCl=1.79mol/kg=1.79m`

Hence, the molality of sodium chloride is, 1.79 m