Question

A 2750-pound car is parked on a hill with a slant of 40° from the horizontal. How much force will keep it from rolling down the hill?

Answer 1

1768.25 N

Explanation:

We are given that

Weigh of car=w=2750 pounds

`\theta=40^(\circ)`

We have to find the force required to keep it from rolling down the hill.

Force required to keep it from rolling down the hill=
`wsin\theta`

Substitute the values

Force required to keep it from rolling down the hill=
`2750sin40`

Force required to keep it from rolling down the hill=
`2750*0.643`

Force required to keep it from rolling down the hill=1768.25 N