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An airplane is at a location 800 miles due west of city X. Another airplane is at a distance of 1,200 miles southwest of city X. The angle at city X created by the paths of the two planes moving away from city X measures 60°. What is the distance between the two airplanes to the nearest mile? Assume that the planes are flying at the same altitude. A. 894 miles B. 1,058 miles C. 646 miles D. 1,251 miles

2 Answers

6 votes

Answer:

1058

Explanation:

Plato

User Gosfly
by
5.6k points
1 vote

Answer:

The distance between the two airplanes (to the nearest mile) is 1058 miles.

Explanation:

Use Law of cosines

d = √(800^2 + 1200^2 - 2·800·1200·COS(60°)) = 1058 miles

User Hanswim
by
4.7k points
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