Question

You mix the letters A, C, Q, U, A, I, N, T, A, N, C, and E thoroughly. Without looking, you select one letter. Find P(Q or C) as a fraction, a decimal, and a percent.

Answer 1

P(Q or C) = 0.25

Explanation:

We are given the following in the question:

Letters:

A, C, Q, U, A, I, N, T, A, N, C, E

Total number of observations, n = 12

We have to find the probability that a randomly selected letter is Q or C.

Formula:

`\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}`

P(Q or C) =

`=\frac{\text{n(Q or C)}}{n} = (3)/(12) =0.25 = 25\%`

Thus,

P(Q or C) = 0.25