1 Answer

Pradyumna · Answer 1 · 2021-06-30T17:01:41+0000

Step-by-step explanation:

Given that,

Wavelength of light,
$\lambda=600\ nm=6* 10^(-7)\ m$

Angle,
$\theta=25^(\circ)$

We need to find the slit spacing for diffraction. For a diffraction, the first order principal maximum is given by :

$d\sin\theta=n\lambda$

n is 1 here

d is slit spacing

$d=(\lambda)/(\sin\theta)\\\\d=(6* 10^(-7))/(\sin(25))\\\\d=1.41* 10^(-6)\ m\\\\d=1.41\ \mu m$

So, the slit spacing is
$1.41\ \mu m$ .

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