Question

A ray in air hits the surface of water at 41.0 deg. At what angle does it travel in the water?

(Unit=deg)

Answer 1

29.53

Step-by-step explanation:

right on acellus

Answer 2

r = 29.53 degrees

Step-by-step explanation:

Given that,

Angle of incidence,
`i=41^(\circ)`

We need to find the angle at which it will travel in the water. The refractive index of water is 1.33 and refractive index of air is 1. Using Snell's law as :

`n_1\sin i=n_2\sin r`

r is the angle of refraction

`\sin r=(n_1)/(n_2)\sin i\\\\\sin r=(1)/(1.33)* \sin (41) \\\\r=\sin^(-1)(0.493)\\\\r=29.53^(\circ)`

So, the ray will travel at an angle of 29.53 degrees in the water.