Answer:
y = 340 students
Explanation:
Solution:-
- The sample of size, n = 500 part time students
- The random variable "X" is defined : annual incomes of part time students. The random variable "X" follows normal distribution with the following parameters (mean income, standard deviation):
X ~ N ( 30,000 , 3,000)
- The proportion of students p that earn between $27,000 and $33,000 are defined by:
p = P ( 27,000 < X < 33,000 )
- Standardize the test values:
P ( (27,000 - 30000) / 3000 < Z < (33,000 - 30000) / 3000 )
P ( - 1 < Z < 1 )
- The empirical rule for the 68 - 95 - 99.7, states:
p = P ( - 1 < Z < 1 ) = 0.68
- So the number of students "y" that get their income between $27,000 and $33,000 are 68% of the sample taken:
y = 0.68*500
y = 340 students