Question

3. Graph the following line 3x – 4y +12 = 0

(put in y=mx+b form first)


PLS HELP ME

Answer 1

y= 3/4x + 3 (-8, -3) (-4, 0) (0, 3) (4, 6) (8, 9)

Explanation:

for y=mx+b form

1. move the expression to the right and change its sign

-4y= -3x - 12

2. change the signs on both sides of the equation

4y= 3x+12

3. divide both sides by 4

y= 3/4x + 3

for graphing

1. plot a point at 3 on the y line ( this is your y intercept y=3/4x +3) (0, 3)

2 From there go up 3 on the y line and then go over 4 to the right you should end up at (4, 6)

3 continue repeating this step until you have at least 4 points plotted. the next point should be at (8, 9)

4 you can also go down instead of up. from point 3 on the y line, go down 3 and over to the left 4, you should end up at ( -4, 0) the next point down would be (-8, -3)

Answer 2

The answer to your question is below

Explanation:

Data

Line: 3x - 4y + 12 = 0

Process

1.- Subtract 3x in both sides

3x - 4y - 3x + 12 = -3x

2.- Simplify

- 4y + 12 = -3x

3.- Subtract 12 in both sides

-4y + 12 - 12 = -3x - 12

4.- Simplify

-4y = -3x - 12

5.- Divide by -4 both sides

-4y/-4 = -3x/-4 - 12/-4

6.- Simplify

y = 3/4x + 3

7.- Graph y-intersept (3)

8.- From the number three, count trhee units up and four units to the right (3/4).

9.- Join the points