Question

The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 18 inches. A solid oblique pyramid has an equilateral triangle base with an edge length of 18 inches. What is the height of the triangular base of the pyramid? 9 √ 2 in. 9 √ 3 in. 18 √ 2 in. 18 √ 3 in.

Answer 1

It's the second option 9 √ 3 in

Explanation:

just did it on edge

Answer 2

b.
`9√(3)in`

Explanation:

We are given that

Length of equilateral triangle=a=18 in

Base of oblique pyramid is an equilateral triangle.

We have to find the height of the triangular base of the pyramid

Height of the triangular base of the pyramid,h=
`acos\theta`

We know that each angle of equilateral triangle =60 degree

`\theta=(60)/(2)=30^(\circ)`

Substitute the values

Height of triangular base of the pyramid,h=
`18cos30=18* (\sqrt 3)/(2)`in

Using the value of

`cos30^(\circ)=(\sqrt 3)/(2)`

Height of triangular base of the pyramid,h=
`9√(3)in`

Option b is true.