Question

UuuuLITUNCION

Given the function f(x) = -2x2 + 3 over the closed
interval [-1, 2], what are the extreme values?
Minimum:
Maximum:

Answer 1

Explanation:

hello :

f(x) = -2x²+3

in : [-1, 2] f'(x) = - 4x

f'(x) = 0 means : -4x=0 so : x=0

f(0) = -2(0)²+3 = 3 (Maximum:) because : a= -2 and a<0

in : [-1, 0] f is crasing

in : [-1, 2] f is decrasing

Answer 2

1.-5

2.3

Explanation:

just did it