Question

There are letter tiles in a bag. Four A’s, five B’s, six C’s and five D’s. You select one tile, replace it, and then draw another.

P( A and A)=______

A. 2/5
B. 1/25
C. 4/20
D. 1/20

Answer 1

[B] 1/25

Explanation:

From the given:

There are letter tiles in a bag. Four A’s, five B’s, six C’s and five D’s. You select one tile, replace it, and then draw another.

To Find:

P( A and A)=______

Solution:

Since it given that:

Four A’s, five B’s, six C’s and five D’s.

Thus we have:

A,A,A,A,B,B,B,B,B,C,C,C,C,C,C,D,D,D,D,D

Total number of letters tiles = 20

Probability of selecting A = 4/20 = 1/5

Probability of selecting A = 4/20 = 1/5

P( A and A)= 1/5 × 1/5 = 1/25

Thus, the answer is [B] 1/25

Kavinsky