How much pressure is required to compress 1L volume of air at 1atm pressure to 0.5L

asked Aug 11, 2021 76.9k views

2 votes

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1 vote

Answer:

p2= 2atm

Step-by-step explanation:

using Boyle's law

p1 x v1 = p2 x v2

v1= 1L

p1= 1 atm

p2=?

v2=0.5L

substitute;

1 x 1 = p2 x 0.5

p2= (1 x 1)\ 0.5

p2= 2atm

IrishGringo answered Aug 15, 2021

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