Question

The partial pressure of N2 in the air is 593 mm Hg at 1 atm. What is the partial pressure of N2 in a bubble of air a scuba diver breathes when he is 132 ft below the surface of the water where the pressure is 5.00 atm?

Answer 1

Answer: Partial pressure of
`N_(2)` at a depth of 132 ft below sea level is 2964 mm Hg.

Step-by-step explanation:

It is known that 1 atm = 760 mm Hg.

Also,
`P_{N_(2)} = x_{N_(2)}P`

where,
`P_{N_(2)}` = partial pressure of
`N_(2)`

P = atmospheric pressure

`x_{N_(2)}` = mole fraction of
`N_(2)`

Putting the given values into the above formula as follows.

`P_{N_(2)} = x_{N_(2)}P`

`593 mm Hg = x_{N_(2)} * 760 mm Hg`

`x_{N_(2)}` = 0.780

Now, at a depth of 132 ft below the surface of the water where pressure is 5.0 atm. So, partial pressure of
`N_(2)` is as follows.

`P_{N_(2)} = x_{N_(2)}P`

=
`0.78 * 5 atm * (760 mm Hg)/(1 atm)`

= 2964 mm Hg

Therefore, we can conclude that partial pressure of
`N_(2)` at a depth of 132 ft below sea level is 2964 mm Hg.